Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Test - Page 1180: 1



Work Step by Step

We need to build a table of $ x $ values close to $9$ from the left side and right side and the values of $ f(x)$ for those values of $ x $. $ x= 8.1..........., x= 9.00111111$ This gives: $ f(x)= 5.846049894,......f(x)= 6.000185179$ From the table, we have $\lim_\limits {x \to 9} \dfrac{9-x}{3-\sqrt x}=6$
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