Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.4 - Introduction to Derrivatives - Exercise Set - Page 1174: 7


a) $7$ b) $ y=7x-8$

Work Step by Step

a) Now, $ m_{\tan}=\lim_\limits{ h\to 0} \dfrac{f(2+h)-f(2)}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{[2(2+h)^2-(2+h)-(2+h)]-[2(2)^2-2]}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{2h^2+7h}{h}$ At $(2,6)$; $ m_{\tan}=7$ b) The equation of a line is: $ y=mx+c $ Now, $ y-6=7(x-2) \implies y=7x-8$
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