Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.4 - Introduction to Derrivatives - Exercise Set - Page 1174: 6


a) $-16$ b) $ y=-16x-16$

Work Step by Step

a) Now, $ m_{\tan}=\lim_\limits{ h\to 0} \dfrac{f(-2+h)-f(-2)}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{4(4-4h+h^2)-16}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{-16h+4^2}{h}$ At $(-2,16)$; $ m_{\tan}=-16$ b) The equation of a line is: $ y=mx+c $ Now, $ y-16=-16(x+2) \implies y=-16x-16$
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