## Precalculus (6th Edition) Blitzer

$17,3$
$(f o g) (x)=(3)^2+(3)^2-6(3)-1=27+9-18-1=17$ Now, $\lim_\limits{x \to 4} (f o g) (x)=17$ and $( g o f) (x)=3$ Now, $\lim_\limits{x \to 4} ( g o f) (x)=3$ Answers: $17,3$