Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.2 - Finding Limits Using Properties of Limits - Exercise Set - Page 1154: 53



Work Step by Step

$(f o g) (x)=\dfrac{2}{3/x-1}=\dfrac{2(x-1)}{3}$ Now, $\lim_\limits{x \to 1} (f o g) (x)=\dfrac{2(1-1)}{3}=0$ and $( g o f) (x)=\dfrac{3}{2/x-1}=\dfrac{3x}{2-x}$ Now, $\lim_\limits{x \to 1} ( g o f) (x)=\dfrac{3(1)}{2-1}=3$ Answers: $0,3$
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