## Precalculus (6th Edition) Blitzer

$\frac{1}{16}$
Step 1. There are 8 pies on the wheel (2 red, 2 blue, 2 green, 2 yellow). The probability of landing on a red is $p_r=\frac{2}{8}=\frac{1}{4}$. The probability of landing on a blue is $p_b=\frac{2}{8}=\frac{1}{4}$. Step 2. Since the two spins are independent, the probability of getting a red first and then a blue is the product of the two probabilities. Thus, we have $p=p_r \times p_b =\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}$