Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Test - Page 1127: 18


$ T_1=x^8$ $ T_2=8x^7 y^2$ $ T_3=28x^6 y^4$

Work Step by Step

The formula to compute $ T_{k+1}$ of the expansion is: $ T_{k+1} =\dbinom{n}{k}p^{n-k}q^k $ Given: $(x+y^2)^8$ $ n=8; k=0$ $ T_1=\dbinom{8}{0}x^{8}(y^2)^0=x^8$ $ n=8; k=1$ $ T_2=\dbinom{8}{1}x^{7}(y^2)^1=8x^7 y^2$ $ n=8; k=2$ $ T_3=\dbinom{8}{2}x^{6}(y^2)^2=28x^6 y^4$
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