Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1120: 72



Work Step by Step

Step 1. There are 900 three-digit numbers (100 to 999). Step 2. To form a three-digit number that reads the same forward and backward, the choice of first (thus the third) digit is $9$ (1-9) and the choice of the middle number is $10$ (0-9). Thus there are $90$ possibilities. Step 3. The probability of finding such a number is $\frac{90}{900}=0.1$
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