Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1120: 52

Answer

$\frac{1}{6}$

Work Step by Step

Step 1. The probability of rolling an odd number (1,3,5) the first time is $p_1=\frac{3}{6}=\frac{1}{2}$ Step 2. The probability of rolling a number less than 3 (1,2) the second time is $p_2=\frac{2}{6}=\frac{1}{3}$ Step 3. The two events are independent and the probability of rolling an odd number the first time and a number less than 3 the second time is $p=p_1\times p_2=\frac{1}{6}$
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