Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1119: 32

Answer

$\frac{11}{1105}\approx0.01$

Work Step by Step

Step 1. Choose 3 from 52 cards. There are $_{52}C_3$ ways. Step 2. There are 12 picture cards, and choosing 3 out of 12 gives $_{12}C_3$ ways. Step 3. The probability of 3 picture cards from 52 cards is $p=\frac{_{12}C_3}{_{52}C_3}=\frac{220}{22100}=\frac{11}{1105}\approx0.01$
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