## Precalculus (6th Edition) Blitzer

$\frac{11}{1105}\approx0.01$
Step 1. Choose 3 from 52 cards. There are $_{52}C_3$ ways. Step 2. There are 12 picture cards, and choosing 3 out of 12 gives $_{12}C_3$ ways. Step 3. The probability of 3 picture cards from 52 cards is $p=\frac{_{12}C_3}{_{52}C_3}=\frac{220}{22100}=\frac{11}{1105}\approx0.01$