Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1119: 25


The required probability is, $\frac{1}{12}$

Work Step by Step

There are 36 equally likely outcomes; therefore, the number of elements in the sample is 36, that is, $ n\left( S \right)=36$ Assume $ E $ to be the event of obtaining two numbers which sum to 4; then $ E=\left\{ \left( 1,3 \right),\left( 2,2 \right),\left( 3,1 \right) \right\}$ Therefore, $ n\left( E \right)=3$ Thus, the probability of obtaining two numbers whose sums is 4 is: $\begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{3}{36} \\ & =\frac{1}{12} \end{align}$
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