Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1119: 24


The required probability is, $\frac{1}{2}$

Work Step by Step

We know that the sample space of equally likely outcomes is $\left\{ MMM,MMF,MFM,MFF,FMM,FMF,FFM,FFF \right\}$ Thus $ n\left( S \right)=8$ Assume $ E $ to be the event of obtaining at least two female children; then, we get $ E=\left\{ MFF,FMF,FFM,FFF \right\}$ Therefore, $ n\left( E \right)=4$ So the probability of getting at least two female children is: $\begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{4}{8} \\ & =\frac{1}{2} \end{align}$
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