# Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1049: 66

$-2$

#### Work Step by Step

Here, we have $a_1=-b_1=-4$, $a_2=-b_2=-2$,$a_3=-b_3=0$,$a_4=-b_4=2$,$a_5=-b_5=4$ Thus, $=(\dfrac{2}{-2})^3+(\dfrac{4}{-4})^3$ $=-1+(-1)$ $=-2$

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