## Precalculus (6th Edition) Blitzer

$\sum_{i=1}^{n} \dfrac{4^i}{i}$
In order to set up the summation notation, we must calculate that value which keeps constantly changing. That value will be designated as the $i$ term. The remaining terms would remain constant in the summation notation. Thus, we get the summation notation: $\sum_{i=1}^{n} \dfrac{4^i}{i}$