Answer
$\sum_{k=2}^{16} 2k $
(Other answers are possible.)
Work Step by Step
In order to set up the summation notation, we must calculate that value which keeps constantly changing. That value will be designated as the $i$ term. The remaining terms would remain constant in the summation notation.
Thus, we get the summation notation:
$6+8+10+......+32=\sum_{k=2}^{16} 2k $; for even terms
