#### Answer

$\sum_{k=2}^{16} 2k $
(Other answers are possible.)

#### Work Step by Step

In order to set up the summation notation, we must calculate that value which keeps constantly changing. That value will be designated as the $i$ term. The remaining terms would remain constant in the summation notation.
Thus, we get the summation notation:
$6+8+10+......+32=\sum_{k=2}^{16} 2k $; for even terms