Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.7 - Combinations of Functions; Composite Functions - Exercise Set - Page 259: 77


$f(x)=\sqrt[3] x$ and $g(x)=x^2-9$ (Other solutions are possible.)

Work Step by Step

One possible solution is: $f(x)=\sqrt[3] x$ and $g(x)=x^2-9$, such that $h(x)=(f\circ g)(x)$
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