$f(x)=x^3$ and $g(x)=2x-5$
Work Step by Step
While it is possible that there are multiple ways of expressing $h$ as composites of $f$ and $g$, we can find one solution as $f(x)=x^3$ and $g(x)=2x-5$ such that $h(x)=(f\circ g)(x)$
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