#### Answer

a. $ 3-x$
b. $(-\infty,2]$

#### Work Step by Step

Given $f(x)=x^2+1$ and $g(x)=\sqrt {2-x}, x\leq2$, we have:
a. $(f\circ g)(x)=(\sqrt {2-x})^2+1=3-x$
b. The domain of the above function can be found as $\{x|x\leq2\}$ or $(-\infty,2]$

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Published by
Pearson

ISBN 10:
0-13446-914-3

ISBN 13:
978-0-13446-914-0

a. $ 3-x$
b. $(-\infty,2]$

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