Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.6 - Transformations of Functions - Exercise Set - Page 245: 153

Answer

The dimension of the rectangular yard: length is $27$ yards and width is $14$ yards.

Work Step by Step

Let the width of the rectangular yard be x, that is, $W=x$ Then the length of the rectangular yard will be $\begin{align} & L=W+13 \\ & =x+13 \end{align}$ The perimeter of the rectangle is given by: $P=2\left( L+W \right)$ So, $\begin{align} & P=2\left( L+W \right) \\ & 82=2\left( x+13+x \right) \\ & 82=2\left( 2x+13 \right) \\ & 82=4x+26 \end{align}$ Further, $\begin{align} & 4x=82-26 \\ & 4x=56 \end{align}$ And, $\begin{align} & 4x=56 \\ & x=\frac{56}{4} \\ & =14 \end{align}$ Thus, the width of the rectangle yard is $x=14$. Now we will find the length by substituting $x=14$: $\begin{align} & x+13=14+13 \\ & =27 \end{align}$ Hence, the dimension of the rectangular yard is: length is $27$ yards and width is $14$ yards.
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