Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.6 - Transformations of Functions - Exercise Set - Page 245: 150

Answer

The corresponding point is $\left( a,2b \right)$.

Work Step by Step

Consider the equation $y=2f\left( x \right)$. Since every value of the function obtained is to be multiplied by the number 2, the graph would look stretched vertically. Thus, multiply the $y$ coordinate of the function $y=f\left( x \right)$ by a factor of 2. Therefore, the point $\left( a,b \right)$ on the graph of $y=f\left( x \right)$ corresponds to a point $\left( a,2b \right)$ on the graph of the function $y=2f\left( x \right)$.
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