Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.6 - Transformations of Functions - Exercise Set - Page 245: 146

Answer

The function is $g\left( x \right)=-\left| x-5 \right|+1.$

Work Step by Step

The graph of $g\left( x \right)$ is obtained by doing a transformation in the graph of $f\left( x \right)=\left| x \right|.$ The vertex of the function $f\left( x \right)=\left| x \right|$ is at the origin. The vertex of the function $g\left( x \right)$ is at $x=5$, so the graph of $f\left( x \right)=\left| x \right|$ will be shifted 5 units towards the right. $f\left( x \right)=\left| x \right|$ , $c=5.$ Then, the function becomes $\begin{align} & h\left( x \right)=\left| x-c \right| \\ & =\left| x-5 \right| \end{align}$ The graph of $g\left( x \right)$ is a shifted reflection of the graph of $f\left( x \right)=\left| x \right|$ along the x axis. Thus, the coordinates of the $y\text{-}$ axis are multiplied by $-1$. So, the function becomes $\begin{align} & h'\left( x \right)=-h\left( x \right) \\ & =-\left| x-5 \right| \end{align}$ Now, the transformed graph is shifted vertically upward by 1 unit; thus, the y-coordinates of all the points of the graph are increased by 1 unit. Thus, add 1 to the function. Therefore, the final function will become $\begin{align} & g\left( x \right)=h'\left( x \right)+1 \\ & =-\left| x-5 \right|+1 \end{align}$ Hence, the function is $g\left( x \right)=-\left| x-5 \right|+1$.
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