Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.5 - More on Slope - Exercise Set - Page 226: 9


point-slope form: $y-2=\frac{2}{3}(x+2)$ general form: $2x-3y+10=0$

Work Step by Step

Step 1. As the line is parallel to line $2x-3y-7=0$, we have its slope $m=\frac{2}{3}$ Step 2. As the line passes through point $(-2,2)$, we can write the line equation in point-slope form as $y-2=\frac{2}{3}(x+2)$ Step 3. The above equation can be rewritten in general form as $3y-6=2x+4$ or $2x-3y+10=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.