#### Answer

point-slope form: $y-2=\frac{2}{3}(x+2)$
general form: $2x-3y+10=0$

#### Work Step by Step

Step 1. As the line is parallel to line $2x-3y-7=0$, we have its slope $m=\frac{2}{3}$
Step 2. As the line passes through point $(-2,2)$, we can write the line equation in point-slope form as $y-2=\frac{2}{3}(x+2)$
Step 3. The above equation can be rewritten in general form as $3y-6=2x+4$ or $2x-3y+10=0$