Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.5 - More on Slope - Exercise Set - Page 226: 10


point-slope form: $y-3=\frac{3}{2}(x+1)$ general form: $3x-2y+9=0$

Work Step by Step

Step 1. As the line is parallel to the line $3x-2y-5=0$, we have its slope $m=\frac{3}{2}$ Step 2. As the line passes through the point $(-1,3)$, we can write the line equation in point-slope form as $y-3=\frac{3}{2}(x+1)$ Step 3. The above equation can be rewritten in general form as $2y-6=3x+3$ or $3x-2y+9=0$
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