Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.3 - More on Functions and Their Graphs - Exercise Set - Page 200: 141

Answer

The value of A is \[\frac{C}{1+r}\].

Work Step by Step

Consider the equation, $C=A+Ar$ Take out $A$ from the right side of the equation. $C=A\left( 1+r \right)$ Divide both sides by $\left( 1+r \right)$. $\begin{align} & \frac{C}{1+r}=\frac{A\left( 1+r \right)}{1+r} \\ & \frac{C}{1+r}=A \end{align}$ Therefore, the value of $A$ is $\frac{C}{1+r}$.
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