#### Answer

The difference quotient of a function is obtained by substituting the values of $f\left( x \right)\text{ and }f\left( x+h \right)$ in the difference quotient formula and solving the equation.

#### Work Step by Step

The difference quotient of a function is obtained by substituting the values of $f\left( x \right)\text{ and }f\left( x+h \right)$ in the difference quotient formula and solving the equation.
Consider the given function $f\left( x \right)$ and the difference quotient formula $\frac{f\left( x+h \right)-f\left( x \right)}{h}$.
To obtain the difference quotient formula of a function, substitute $x=x+h$ and then put the function in the formula.
$\frac{f\left( x+h \right)-f\left( x \right)}{h}$
Example:
Consider the following function as an example:
$f\left( x \right)={{x}^{2}}+x+1$
Substitute $x+h$ in the place of $x$ as follows:
$\begin{align}
& f\left( x+h \right)={{\left( x+h+1 \right)}^{2}}+\left( x+h \right)+1 \\
& f\left( x \right)={{x}^{2}}+x+1
\end{align}$
Now, substitute the values of $f\left( x \right)\text{ and }f\left( x+h \right)$ in the difference quotient formula as follows:
$\begin{align}
& \frac{f\left( x+h \right)-f\left( x \right)}{h}=\frac{\left( {{\left( x+h+1 \right)}^{2}}+\left( x+h \right)+1 \right)-\left( {{x}^{2}}+x+1 \right)}{h} \\
& =\frac{{{h}^{2}}+2hx+3h+2x+1}{h}
\end{align}$
Thus, to get the difference quotient formula, the value of x is substituted.