## Precalculus (6th Edition) Blitzer

To find the x and y intercepts of the line, substitute $x=0\text{ and }y=0$ one by one. Put $x=0$ \begin{align} & 2\left( 0 \right)-y-10=0 \\ & -y-10=0 \\ & y=-10. \\ \end{align} So, we get one point on the y-axis through which the given line passes: $\left( -10,\ 0 \right)$ Now, put $y=0$ \begin{align} & 2x-0-10=0 \\ & 2x-10=0 \\ & 2x=10 \\ & x=5. \end{align} So, the second point that lies on the line will be $\left( 5,\ 0 \right)$. Therefore, the line will pass through two points, cutting the x and y axes at the points $\left( 5,\ 0 \right)$ and $\left( -10,\ 0 \right),$ respectively.