## Precalculus (6th Edition) Blitzer

(a) Provided function g\left( x \right)=\left\{ \begin{align} & \sqrt{x-4}\text{ if }x\ge \text{4} \\ & 4-x\text{ if }x\text{ 4} \\ \end{align} \right.. To find $g\left( 13 \right)$, put $x=13$ in function $g\left( x \right)=\sqrt{x-4}$. When $x\ge 4$, \begin{align} & g\left( x \right)=\sqrt{x-4} \\ & g\left( 13 \right)=\sqrt{13-4} \\ & =\sqrt{9} \\ & =3. \end{align} (b) Let us consider the provided function g\left( x \right)=\left\{ \begin{align} & \sqrt{x-4}\text{ if }x\ge \text{4} \\ & 4-x\text{ if }x\text{ 4} \\ \end{align} \right.. To find $g\left( 0 \right),$ put $x=0$ in function $g\left( x \right)=4-x$. When $x<4,$ \begin{align} & g\left( x \right)=4-x \\ & g\left( 0 \right)=4-0 \\ & =4 \end{align} (c) Let us consider the provided function g\left( x \right)=\left\{ \begin{align} & \sqrt{x-4}\text{ if }x\ge \text{4} \\ & 4-x\text{ if }x\text{ 4} \\ \end{align} \right.. To find $g\left( -3 \right)$, put $x=-3$ in function $g\left( x \right)=4-x$. When $x<4$, \begin{align} & g\left( x \right)=4-x \\ & g\left( -3 \right)=4-\left( -3 \right) \\ & =7 \end{align}