Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 300: 19

Answer

The provided equation is $3{{x}^{2}}+y=14$ defines y as a function of x.

Work Step by Step

Let us the consider the following equation: $3{{x}^{2}}+y=14$ Isolate y on the left in the above equation, $y=-3{{x}^{2}}+14$ The above equation will provide a unique value of y for a different value of x. Again, apply the vertical line test according to which if any vertical line (parallel to the x-axis) intersects the provided graph into two different points then it is not a function. Since the graph of the equation will be a downward facing parabola, thus no vertical line will intersect the graph in more than one point. Thus, the above equation defines y as a function of x.
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