Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 300: 20

Answer

The given equation is $2x+{{y}^{2}}=6$ does not define y as a function of x.

Work Step by Step

Let us the consider the following equation: $2x+{{y}^{2}}=6$ Isolate y on the left in the above equation $y=\sqrt{6-2x}$ The above equation will not provide a unique value of y for different values of x as there can be a negative as well as a positive value. Apply the vertical line test according to which if any vertical line (parallel to the x-axis) intersect the provided graph into two different points then it is not a function. The graph of the equation will be a left facing parabola so more than one vertical line will cross the graph in more than one point. So, the above equation does not define y as a function of x.
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