Answer
$2\sqrt{10}$
Work Step by Step
The magnitude of a vector $v=ai+bj$ is: $||v||=\sqrt{a^2+b^2}$.
Hence, here we have
$||v||
\\=\sqrt{6^2+2^2}
\\=\sqrt{36+4}
\\=\sqrt{40}
\\=\sqrt{4(10)}
\\=2\sqrt{10}$
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