Answer
$5$
Work Step by Step
The magnitude of a vector $v=ai+bj$ is: $||v||=\sqrt{a^2+b^2}$.
Hence, here we have
$||v||
\\=\sqrt{3^2+(-4)^2}
\\=\sqrt{9+16}
\\=\sqrt{25}
\\=5$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 9 - Polar Coordinates; Vectors - 9.4 Vectors - 9.4 Assess Your Understanding - Page 606: 37
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