Answer
$8i-j.$ This is also the position vector.
Work Step by Step
If a vector $v$ initiates at point $P(x_1,y_1)$ and terminates at $Q(x_2,y_2)$ then $v=(x_2-x_1,y_2-y_1)=(x_2-x_1)i+(y_2-y_1)j.$ Hence here $v=(6-(-2)))i+(-2-(-1))j=8i-j.$ This is also the position vector.
