Work Step by Step
If a vector $v$ initiates at point $P(x_1,y_1)$ and terminates at $Q(x_2,y_2)$ then $v=(x_2-x_1,y_2-y_1)=(x_2-x_1)i+(y_2-y_1)j.$ Hence here $v=(3-0)i+(4-0)j=3i+4j.$ The position vector is $(3,4)$.
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