Answer
$(3, 0)$
Work Step by Step
We know that if the rectangular coordinates of the point are $(x,y)$, then
$r=\sqrt{x^2+x^2}$ and $\theta=\tan^{-1}(\frac{y}{x})$.
Hence here:
$r=\sqrt{3^2+0^2}=3$
$\theta=\tan^{-1}\left(\frac{0}{3}\right)=0$
The given point has the polar coordinates $(3,0)$.
