Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - 9.1 Polar Coordinates - 9.1 Assess Your Understanding - Page 572: 57


$(3, 0)$

Work Step by Step

We know that if the rectangular coordinates of the point are $(x,y)$, then $r=\sqrt{x^2+x^2}$ and $\theta=\tan^{-1}(\frac{y}{x})$. Hence here: $r=\sqrt{3^2+0^2}=3$ $\theta=\tan^{-1}\left(\frac{0}{3}\right)=0$ The given point has the polar coordinates $(3,0)$.
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