Answer
$\left(\frac{5}{2},-\frac{5\sqrt3}{2}\right)$
Work Step by Step
By definition: $x=r\cdot \cos(\theta)$ and $y=r\cdot \sin(\theta)$.
Here $r=5, \theta=300^\circ$.
Hence, after plugging these in:
$x=5\cdot \cos(300^\circ)=5\cdot(0.5)=\frac{5}{2}$
$y=5\cdot \sin(300^\circ)=5\cdot(-\frac{\sqrt3}{2})=-\frac{5\sqrt3}{2}$
The point has coordinates $\left(\frac{5}{2},-\frac{5\sqrt3}{2}\right)$ in the rectangular coordinate system.
