Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - 9.1 Polar Coordinates - 9.1 Assess Your Understanding - Page 572: 52

Answer

$(0,3)$

Work Step by Step

By definition we have $x=r\cdot \cos(\theta)$ and $y=r\cdot \sin(\theta)$. Here we have $r=-3 \text{ and }\theta=-90^\circ$. Hence, after plugging these in: $x=-3\cdot \cos(-90^\circ)=-3\cdot0=0$ $y=-3\cdot \sin(-90^\circ)=-3\cdot(-1)=3$ The point has coordinates $(0,3)$ in the rectangular coordinate system.
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