Answer
$(-3\sqrt3,3)$
Work Step by Step
By definition: $x=r\cdot \cos(\theta)$ and $y=r\cdot \sin(\theta)$.
Here $r=6 \text{ and } \theta=150^\circ$.
Hence, after plugging these in:
$x=6\cdot \cos(150^\circ)=6\cdot(-\frac{\sqrt3}{2})=-3\sqrt3$
$y=6\cdot \sin(150^\circ)=6\cdot(\frac{1}{2})=3$
The point has coordinates $(-3\sqrt3,3)$ in the rectangular coordinate system.
