Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Trigonometry and Periodic Functions - 7.1 The Inverse Sine, Cosine, and Tangent Functions - 7.1 Assess Your Understanding - Page 451: 69

Answer

$ -\frac{1}{4} $

Work Step by Step

$cos^{-1}(2x)=\frac{2\pi}{3} \longrightarrow 2x=cos\frac{2\pi}{3}=-\frac{1}{2} \longrightarrow x=-\frac{1}{4} $
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