Precalculus (10th Edition)

by Sullivan, Michael

Published by Pearson

ISBN 10: 0-32197-907-9

ISBN 13: 978-0-32197-907-0

Chapter 7 - Trigonometry and Periodic Functions - 7.1 The Inverse Sine, Cosine, and Tangent Functions - 7.1 Assess Your Understanding - Page 451: 57

Answer

$\pi$

Work Step by Step

We know that $f(f^{-1}(x))=x$. Hence, $\tan\left(\tan^{-1}(\pi)\right)=\pi$

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