Answer
$ -\frac{1}{6} $
Work Step by Step
$sin^{-1}(3x)=-\frac{\pi}{6} \longrightarrow 3x=sin(-\frac{\pi}{6})=-\frac{1}{2} \longrightarrow x=-\frac{1}{6} $
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Trigonometry and Periodic Functions - 7.1 The Inverse Sine, Cosine, and Tangent Functions - 7.1 Assess Your Understanding - Page 451: 70
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