Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Trigonometry and Periodic Functions - 7.1 The Inverse Sine, Cosine, and Tangent Functions - 7.1 Assess Your Understanding - Page 451: 14

Answer

(a).

Work Step by Step

$f(x)=\frac{1}{2}tan(x) \longrightarrow y=\frac{1}{2}tan(x) \longrightarrow x=\frac{1}{2}tan(y) \longrightarrow y=tan^{-1}(2x) \longrightarrow f^{-1}(x)=tan^{-1}(2x)$. Thus the answer is (a).
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