Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.3 Trigonometric Equations - 7.3 Assess Your Understanding - Page 466: 58

Answer

$2.42,3.86$

Work Step by Step

$4cos\theta+3=0 \longrightarrow cos\theta=-\frac{3}{4} \longrightarrow \theta=cos^{-1}(-\frac{3}{4})=\pi\pm cos^{-1}(\frac{3}{4})\approx\pi\pm0.723$. Thus $\theta\approx2.42,3.86$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.