Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.3 Trigonometric Equations - 7.3 Assess Your Understanding - Page 466: 14

Answer

$\left\{\dfrac{\pi}{3}, \dfrac{5\pi}{3}\right\}$

Work Step by Step

$1-\cos\theta=0.5$ $1-0.5=\cos{\theta}$ $0.5=\cos\theta$ Since $0\le\theta\lt2\pi$, then $\theta=\dfrac{1}{3}\pi$ $\theta=\dfrac{5}{3}\pi$
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