Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.3 Trigonometric Equations - 7.3 Assess Your Understanding - Page 466: 13

Answer

$\left\{\dfrac{7}{6}\pi, \dfrac{11}{6}\pi\right\}$

Work Step by Step

$2\sin\theta+3=2$ $2\sin\theta=-1$ $\sin\theta=-0.5$ Since $0\le\theta\lt2\pi$, then $\theta=\dfrac{7}{6}\pi$ $\theta=\dfrac{11}{6}\pi$
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