Answer
$1.37, 4.51$.
Work Step by Step
The domain of $\tan^{-1}{x}$ is the range of $\tan{x}$, which is the real numbers.
The range of $\tan^{-1}{x}$ is a specified domain of $\tan{x}$, i.e. $\left(− \frac{\pi}{2} , \frac{\pi}{2} \right)$.
After using a calculator in radian mode the solutions for $\tan^{-1}{5}$ is $1.37$ (given by the calculator) and because the tan function has a period of $\pi$ the second solution is: $1.37+\pi\approx4.51$.
