Answer
$ 2+3log_2x-log_2(x-6)-log_2(x+3)$
Work Step by Step
$log_2(\frac{4x^3}{x^2-3x-18})=log_24+log_2x^3-log_2(x^2-3x-18)=2+3log_2x-log_2[(x-6)(x+3)]=2+3log_2x-log_2(x-6)-log_2(x+3)$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Chapter Test - Page 348: 20
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