Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Chapter Test - Page 348: 16

Answer

$x=-\ln{2}$

Work Step by Step

$8-2e^{-x}=4\\-2e^{-x}=-4\\e^{-x}=2\\\ln{e^{-x}}=\ln{2}\\-x=\ln{2}\\x=-\ln{2}$
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