Answer
$\frac{1\pm\sqrt {13}}{2}$
Work Step by Step
Step 1. From the given equation, we have $x^2+3=x+6 \longrightarrow x^2-x-3=0 \longrightarrow x=\frac{1\pm\sqrt {1+12}}{2}=\frac{1\pm\sqrt {13}}{2}$
Step 2. Check answers, they both fit.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Chapter Test - Page 348: 17
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