Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Chapter Test - Page 348: 14

Answer

$\{1\}$

Work Step by Step

Note that $125=5^3$. Thus, the given equation is equivalent to $5^{x+2}=5^3.$ RECALL: If $a\ne1$ and $a\ne-1$ then $a^x=a^y\longrightarrow x=y$ Hence, $5^{x+2}=5^3 \longrightarrow x+2=3$ Solve the equation above to obtain $x+2=3\\ (x+2)-2=3-2\\ x=1$ The solution set is:$\{1\}.$
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