Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 7



Work Step by Step

The Change of Base of formula says: $log_a b=\frac{log_c b}{log_c a}$, hence $\frac{log_5 7}{log_5 8}=log_8 7$. Thus, if $log_8 7=log_8 M$, then $M=7.$
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